x+x^(1/2)-6=0

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Solution for x+x^(1/2)-6=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x+x^(1/2)-6 = 0

t_1 = x^(1/2)

1*t_1^2+1*t_1^1-6 = 0

t_1^2+t_1-6 = 0

DELTA = 1^2-(-6*1*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)-1)/(1*2) or t_1 = (-25^(1/2)-1)/(1*2)

t_1 = 2 or t_1 = -3

t_1 = -3

x^(1/2)+3 = 0

1*x^(1/2) = -3 // : 1

x^(1/2) = -3

( -3 < 0 i 1/2 in (0:1) ) => x naleu017Cy do O

t_1 = 2

x^(1/2)-2 = 0

1*x^(1/2) = 2 // : 1

x^(1/2) = 2

x^(1/2) = 2 // ^ 2

x = 4

x = 4

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